f(sin(theta), cos(theta), rsin(theta)) find surface area what is the answer?theta is between 0 and 2pi and r is between 0 and 1
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f(sin(theta), cos(theta), rsin(theta)) find surface area what is the answer?theta is between 0 and 2pi and r is between 0 and 1
can u just tell me an answer?newbie4lyfeAnd this is the problem with the "education" system these days. You are doing this problem to learn "how" the equation works, the answer doesn't matter. Why do they ask you to show all your work if they just want the solution? If you just want the answer, check the back of the textbook in the answer key. But joke's on you, they only give you the solution, and you don't get marks for a partial answer.
That question isn't even hard... If you seriously don't have the mental capacity to go look up a cookie cutter formula in a mathbook, and instead resort to an online forum not even dedicated to this stuff, then why are you even bothering with whatever it is you are reading?
As others have said, at least set it up first. It isn't a hard problem. On a side note, double integrals and the majority of multivariate calculus is pretty much supplementary information to everyone but a select few physical science majors.
As others have said, at least set it up first. It isn't a hard problem. On a side note, double integrals and the majority of multivariate calculus is pretty much supplementary information to everyone but a select few physical science majors.
Saturos3091
What do you even mean? Are you saying that f is some function of the vector (sin(theta), cos(theta), rsin(theta))? You haven't even specified your limits properly.
Well, if you want to integrate f over those limits then obviously we can't tell you what that is if you're not going to tell us what f is. So, I'm going to assume that instead of that you just want the area integral. The answer isn't 0, and in fact should be obvious if you consider what shape you're finding the area ofyes and re-edited my post
newbie4lyfe
Well, if you want to integrate f over those limits then obviously we can't tell you what that is if you're not going to tell us what f is. So, I'm going to assume that instead of that you just want the area integral. The answer isn't 0, and in fact should be obvious if you consider what shape you're finding the area of[QUOTE="newbie4lyfe"]
yes and re-edited my post
MannyDelgado
not zero, ok thank you for your coop
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