So why did you say that when you add to an infinite set, it doesn't become larger, just below?
danwallacefan
...Because it doesn't. I have no idea what you're talking about here.
well not exactly. Like you said, if process 1 is used, then the shift never happens because its constantly happening and this will take an infinite amount of time (or rather, will never happen). But if process 2 is used, then the absurdities in Hilbert's Hotel and various other examples will arise.Â
danwallacefan
No, no they don't. In both cases, the exact same people end up in the exact same room. If you wish to dispute this, then find me a person who ends up roomless in process 2 who does not meet the same fate (eventually) in process 1.
But this is a simple rule of logic is it not? To add to some set, any set, is to take something external to that set and add to that set, thereby expanding that set.
danwallacefan
Yes...
...but if the set is infinite, then the change in size is zero.
I'm "bluffing my case through unnecessarily technical language"?
danwallacefan
Considering that the ultimate question is "Is there a contradiction?", and considering that you are attempting to use that language to ignore that question and instead assume an answer to it off the bat, yes.
Okay, lemme dumb it down for you.Â
If you add X to Y, Y becomes larger.Â
You have added X to Y
Therefore, Y isn't larger?
danwallacefan
The ultimate question we are addressing is precisely that very first premise. That you are unwilling to even acknowledge that it is in question, and that you instead insist on asserting that I am violating basic logical principles by utterly assuming its truth and proceeding from there, is curious.
The percent increase in Y by adding the contents of X to Y is given by the simple division |X|/|Y|, where |A| is the size of a given set A. Suppose that the size of X is 1, and that the size of Y is also 1. In this case, the percent increase is 100% - you have doubled the size of Y. Now, suppose you add another item to Y. Now, the percent increase is 50%. If you keep going, the percent increase steadily decreases - 33%, 25%, 20%, and so on. Therefore, it is easy to see how, if the size of Y is infinite, the percentage increase from adding an item to it is precisely zero.
Thus, no, modus ponens has not been defeated for the simple fact that the conditional statement is false. Adding an item to an infinite set does not change the size of the set. If it did, then the set would not be infinite.
Modus ponens. Learn about it.
danwallacefan
If one were to learn about it, one would presumably discover that "if A, then B" must be true before B can be derived from A.
Here you are simply misunderstanding my point. How you managed to interpret my blanket statement "Mathematicians accept that infinites are just concepts with no bearing on reality" as "Mathematicians accept this, therefore this is correct" is beyond me.
danwallacefan
I will leave any final judgment regarding what you said and what it meant to the observer.
But I'll play along and assume that I really did say that
So what? Take a remedial debate ****Gabu, an appeal to authority is only fallacious if the authority to which we are appealing is not an actual authority.Â
The consensus of mathematicians on a mathematical issue, of course, IS an authority.
danwallacefan
Debate cIass? I was under the impression that we are discussing mathematics and logic. Or was all that mention of the law of non-contradiction and modus ponens just for show?
This is not a "debate". One may have a debate over an "ought", or one may have a debate over an "is" that can never be conclusively proven, but we are in neither scenario. When it comes to mathematics and logic, there is only one credible authority: the rigorously constructed argument. And you have failed to provide any such argument at all, instead simply making the same unsupported assertion again and again.
If you wish to prove that an infinite cannot exist in reality, then I have already given you two paths that you can take. You can either show why a hotel's room assignments cannot be accurately modeled by two sets and a function between them, or you can show why the math that I have employed is faulty. Either will do - but failure to attempt either is a tacit admission both that the model is accurate and that the math is sound, which will leave your argument in rather dire straits.
If you could explain, in layman's terms, How your appeal to a coordinate plain works here, that would be great.
danwallacefan
It's simple: to determine whether or not sets A and B are the same size, you simply match elements from A with elements from B.
If you can show that every element of A can be matched with one and only one element of B, then you have shown that the size of A is less than or equal to the size of B. This intuitively makes sense, as it would indicate that there are at least as many elements in B as in A.
If you can show that every elements of B can be matched with one and only one element of A, then you have shown that the size of A is greater than or equal to the size of B.  This also intuitively makes sense, as it would indicate that there are at least as many elements in A as in B.
If you can show that both of these can be done simultaneously, then you have shown that the size of A is equal to the size of B, as the only way that a number can be both greater than or equal to and less than or equal to a number is if it is precisely equal to that number.
And this is precisely what I have done: I have shown that a mapping can be made between B and B' such that every element in B is mapped with one and only one element of B', and also such that every element of B' is mapped with one and only one element of B - thus proving that they are the same size.
Now, let's use this analogy more in line with the question of actual infinites, because your analogy is just appealing to two different sets on different axis on a graph while smuggling in the conclusion that Set B really has elements of Set A, but is still not expanded. Â
Set 1={2, 4, 6, 8...}
Set 2={1, 3, 5, 7...}
Now, if we added these 2 sets to eachother, we get Set 3, {1, 2, 3, 4...}
Now, is set 3 larger than sets 1 or 2? If not, then how is this not contradictory? If yes, then how so, if they are both, to use your words, "countably infinite"?
danwallacefan
Well, first, I should explain the phrase "countably infinite", since it sounds as though that might be an unfamiliar term. A set that is countably infinite is one which contains an infinite number of elements, but in which every single element is enumerable. The set of natural numbers is an example of that - one can simply count off the numbers in it: 1, 2, 3, and so on. The alternative is an uncountably infinite set. This is a set like the real numbers, where elements within the set are themselves infinite, and therefore not every element is enumerable.
I use the qualifying phrase "countably infinite" rather than just infinite, because there is a fact about uncountably infinite sets that is at face value curious - namely, that they are strictly larger than countably infinite sets. I could rigorously prove this, but it's not relevant to this discussion - suffice it to say that it's because there are two orders of infinity at play rather than just one; not only are there an infinite number of elements, but such a set contains elements which are themselves also infinite. Thus, in order to preserve mathematical rigor, I need to specify precisely what order of infinity I am talking about.
But, let's go back to your example. In it, we have two sets: A = {2, 4, 6, 8, ...} and B = {1, 3, 5, 7, ...}. The question is asked: is the union of these sets C = A U B = {1, 2, 3, 4, ...}, larger than either of the two sets alone?
The answer is no. And the answer to the followup question - how is this not contradictory? - goes back to what I said above. If a set is already infinite, then adding more elements to it does not change its size, despite the fact that it changes the elements within the set. And though in the example before only tackled the case of adding a single item to it, it is in fact the case that even adding up to a countably infinite number of items to the set does not change its size. If it were the case that 2 * |A| > |A|, then |A| would be finite.
I could set up a mapping just like the one I showed earlier in order to prove this, but I'm sure that is an exercise that you yourself could do - it's not hard, really. You just need to figure out what function would transform {2, 4, 6, 8, ...} into {1, 2, 3, 4...}.
So, in conclusion, is C larger than A or B? No.
But, is this a contradiction? No. It's just the nature of infinity.
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