[QUOTE="GabuEx"][QUOTE="dave123321"][QUOTE="GabuEx"] [QUOTE="DeeJayInphinity"]There are 201 people. One person has green eyes; the guru. 100 have brown eyes and every person with blue eyes counts 99 with blue eyes.. After 100 nights, the Guru has counted 100 blue eyes. Everyone with blue eyes would leave because if 101 people have non-blue eyes, and 99 people have blue eyes, that must mean they have blue eyes because 101(non blue eyes)+99(blue eyes)= 200, which would logically mean that THEY have blue yes. Everyone with blue eyes would realize this, and leave.diped
But that's the thing, the Guru isn't counting blue eyes. She just says once and only once (as the premise goes) that someone has blue eyes. If she was naming different people each day that had blue eyes, it would be totally different, but as the premise stands right now, it's in my opinion that the riddle doesn't work.
No one has the knowledge that there are only blue eyes and brown eyes(except the guru I suppose). They could have green , red, polka dot eyes for all that they know. The guru gives them the ability to sort for blue eyes.
But it was specified in the riddle that everyone can see everyone else. That means that the Guru knows there are 100 blue eyes and 100 brown eyes, that blue-eyed people know that there are 99 blue eyes, 100 brown eyes, and 1 green eye, and that brown-eyed people know that there are 100 blue eyes, 99 brown eyes, and 1 green eye. The only unknown for anyone is the color of their own eyes.
All that the Guru tells them is that there is someone with blue eyes. Everyone already knew that. This is a riddle that tries to make people employ a clever technique, but fails to give people proper justification to do so. I still believe that if people only strictly stick to the premise given in the first post, then this puzzle is unsolvable.
Its very solvable. If your a blue eyed person, you see 99 other blue eyed people. So you know that if you were any colour other than blue, the 99 blue eyed people would leave, but on the 100th day no on leaves, so you know you are blue eyed and must leave.
The # of brown eyed people don't really matter. So...
To make it simpler, use 2 blue eyed people. You have blue eyes(though you don't know yet), you see the other person has blue eyes. So you know that if the other person sees that you have brown eyes, the other person would leave on the 1st day. But on the 2nd day, you see that they did not leave on the 1st day, now you each know that you both have blue eyes, and must both leave the island on the 2nd day.
The same happens with 3 blue eyed people. You see 2 blue eyed people. You know that if you had brown/red/green/whatever eyes, they would both leave on the 2nd day. They did not leave, now you know taht you have blue eyes, and must leave on the 3rd day.
4 people: You see 3 blue eyed people, you know that if you had nonblue eyes, they would have left on the 3rd day, they do not. On the 4th day, you know that you have blue eyes, and must leave.
5 people: You see 4 blue eyed people, you know that if you had nonblue eyes, theyw ould leave on the 4th day, but they do not. On the 5th day you know that you have blue eyes, and must leave.
6 people: you see 5 blue eyed people, you know that if you had non blue eyes, they would leave on the 5th day, but they do not. On the 6th day you know that you hve blue eyes, and must leave.
etc...
etc...
100 people: You see 99 other blue eyed people. You know that if you had nonblue eyes, they would leave on the 99th day, they do not, you now know that you have blue eyes, and must leave the island on the 100th day. this is the best explanation imo.
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