We will assume that the arc is a parabola facing down.

Then the equation of the parabola would be:

f(x) = -ax^2 + bc + c

Now we will assume that the highest point is on the y-axis. Then the point ( 0,6) is the maximum point.

Now we will assume...

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We will assume that the arc is a parabola facing down.

Then the equation of the parabola would be:

f(x) = -ax^2 + bc + c

Now we will assume that the highest point is on the y-axis. Then the point ( 0,6) is the maximum point.

Now we will assume that the endpoints of the parabola is on the x-axis where the distance is 12 m.

Then the endpoints are ( 6, 0) and (-6, 0)

We will substitute and determine a, b , and c.

First we will substitute ( 0, 6)

==> f(0) = c = 6

==> c = 6

Now we will substitute 6 and -6/

==> f(6) = -36a + 6b + 6 = 0

==> -6a + b + 1 = 0 .............(1)

f(-6) = -36a - 6b + 6 = 0

==> -6a -b + 1 = 0............(2)

Now we will add (1) and (2).

==> -12a + 2 = 0

==> a = 1/6

==> b= -6a+ 1 = 0

==> b= 0

==> f(x) = -(1/6)x + 6

Now we need to determine if the trailer of 9 ft wide can fit under the bridge.

If the trailer drive exactly in the middle of the bridge then it will be between the points ( 4.5, 0) and ( -4.5, 0).

Now we need to find out the height of the bridge at these points.

We will substitute with f(4.5).

==>f(4.5) = -(1/6) (4.5)^2 + 6 = 2.635.

Then, the height of the bridge at the points (4.5, 0) is 2.635 m.

But the trailer height is 3.2

**Then, the trailer can not fit under the bridge.**