x^2=x+20 I'm wondering what the answer to this problem is.

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argos163

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#1 argos163
Member since 2006 • 126 Posts

THIS ISN't A HOMEWORK PROBLEM! Geeze.

How would some of you go about solving this?

edit: What would this kindof problem be called anyways?

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ColonelWilks

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#2 ColonelWilks
Member since 2005 • 3149 Posts
X^2 = X+20 X^2 - x -20 = 0 (X-5)(X+4) = 0 X= 5, -4
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Chris_Watters

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#3 Chris_Watters
Member since 2007 • 454 Posts

Problems that can be expressed as AX^2 + BX + C = 0, where A, B, and C are constants are quadratic problems that can be solved using the quadratic formula. Or by factoring as ColonelWilks adeptly demonstrated.

In your example, A = 1, B = -1, and C = -20.